Age Problems( Week 30 Evaluation) 1. Two people have the same two digits for their ages but their ages are in reverse order with each other (i.e. if one is 19 years old, then the other is 91 years old). If the sum of the two digits is 12, and one person is 18 years older than the other, how old is the younger person? 2. The average age of 5 people is 21. None of them are younger than 10 years old. How old is the oldest possible age in the group? 3. Jessica's age is a multiple of 5 this year. Next year it will be a multiple of 6. She is more than 6 years old. At least how old is she now? 4. Jane's age is of George's age this year. 3 years ago, her age was of George's age. How old is Jane now? 5. Emily's age is a multiple of 9 this year. Next year it will be a multiple of 7. At least how old is she now? 6. The sum of the ages of three brothers is 12. The oldest brother is 3 times as old as the youngest one. The ages of the two younger brothers differ by 2 years. What is the age of the brother in the middle? 7. Two people have the same two digits for their ages but their ages are in reverse order with each other (i.e. if one is 19 years old, then the other is 91 years old). If the sum of the two digits is 8, and one person is 18 years older than the other, how old is the older person? 8. Two people have two-digit ages. Both age numbers have a digit sum of 10 and an equal digit product. If one person is 36 years older than the other person, how old is the older person? 9. David is 5 times as old as Susan. Eric is 6 years older than Susan and 7 years younger than Mary. Richard is 4 times as old as Susan. If the sum of the 5 people's ages is 115, how old is David? 10. Susan is 4 times as old as David. However, 3 years later, she will only be 3 times as old as David. How old is David now? |